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Mapping XML

Spin can deserialize XML to Java objects and serialize the annotated Java objects to XML by integrating mapping features into its fluent API. JAXB annotations can be added to the involved Java classes to configure the (de-)serialization process but are not required.

Mapping between Representations:

Assume we have a class Customer defined as follows:

@XmlRootElement(name="customer", namespace="http://camunda.org/test")
public class Customer {

  private String name;

  @XmlElement(namespace="http://camunda.org/test")
  public String getName() {
    return name;
  }

  public void setName(String name) {
    this.name = name;
  }
}

Mapping XML to Java:

We can map the following XML object

<?xml version="1.0" encoding="UTF-8"?>
<customer xmlns="http://camunda.org/example">
 <name>Kermit</name>
</customer>

to an instance of Customer in the following way:

import static org.camunda.spin.Spin.XML;

String xmlInput = "<?xml version=\"1.0\" encoding=\"UTF-8\"?><customer xmlns=\"http://camunda.org/example\"><name>Kermit</name></customer>";

Customer customer = XML(xmlInput).mapTo(Customer.class);

Mapping Java to XML:

We can map the customer back to XML as follows:

import static org.camunda.spin.Spin.XML;

String xml = XML(customer).toString();

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